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[HellRaZoR004]

Originally Posted by HellRaZoR004

Yes, converting binary to decimal. This...

00101100 (0+0+32+0+8+4+0+0), corresponding to the location of each 1/0.

In the following order you count the decimal equivalent of a binary number.

[128 64 32 16 8 4 2 1], if there is a '1' present in the corresponding location that number is added. If a '0' is present in the corresponding location that number is not added.

Therefore [128 64 32 16 8 4 2 1] = [0+0+32+0+8+4+0+0] = [44]